**Description:**

A rectangle with sides equal to even integers `a`

and `b`

is drawn on the Cartesian plane. Its center (the intersection point of its diagonals) coincides with the point `(0, 0)`

, but the sides of the rectangle are not parallel to the axes; instead, they are forming `45`

degree angles with the axes.

How many points with integer coordinates are located inside the given rectangle (including on its sides)?

**Example**

For `a = 6`

and `b = 4`

, the output should be

`rectangleRotation(a, b) = 23`

.

The following picture illustrates the example, and the `23`

points are marked green.

**Input/Output**

**[input] integer a**A positive even integer.
*Constraints:*

`2 ≤ a ≤ 50`

.

**[input] integer b**A positive even integer.
*Constraints:*

`2 ≤ b ≤ 50`

.

**[output] integer**The number of inner points with integer coordinates.

** Tests:**

**Explain:**

therefore 4 blue edges make 45 degrees angles so the 4 edges are corresponding 4 expressions:

- f
_{1}(x,y) = x + y + u = 0
- f
_{2}(x,y) = x + y – u = 0
- f
_{3}(x,y) = x – y + v = 0
- f
_{4}(x,y) = x – y – v = 0

therefore point O(0,0) is in the rectangle, So

- f
_{1}(0,0) = u > 0
- f
_{2}(0,0) = -u < 0
- f
_{3}(0,0) = v > 0
- f
_{4}(0,0) = -v < 0

If 1 point P(x,y) is in the rectangle then demands 4 conditions:

- f
_{1}(x,y) = x + y + u > 0
- f
_{2}(x,y) = x + y – u < 0
- f
_{3}(x,y) = x – y + v > 0
- f
_{4}(x,y) = x – y – v < 0

Mean: |x + y| < u and |x – y| < v

Now finding u, v:

Draws more 2 red lines perpendicular with 2 edges of the rectangle, we have right angled triangles, So u = a/sqrt(2), v = b/sqrt(2).

** Solution(C#):**

int rectangleRotation(int a, int b) {
int r = 0;
for (int x = -a - b; x &amp;amp;amp;amp;lt;= a + b; x++) {
for (int y = -a - b; y &amp;amp;amp;amp;lt;= a + b; y++) {
if (2 * (x - y) * (x - y) &amp;amp;amp;amp;lt;= a * a &amp;amp;amp;amp;amp;&amp;amp;amp;amp;amp; 2 * (x + y) * (x + y) &amp;amp;amp;amp;lt;= b * b)
r++;
}
}
return r;
}